c# - How can i capture local variable in dynamic method? -


this question has answer here:

(i'm new english)

i use expression.lambda dynamically creating lambda.

i want capture variables don't know how capture using expression.

      public class demo     {         /** skip */         private context _context;         public void route(person person)         {             packet packet = packet.getpacket();             func <context, object> lambda =                 (context) => this.othermethod(context, person, packet); //         }         /** skip */     }

i want create lambda(look comment "this") using expression@lambda. it's possible?

this code i'm trying make.(not work)

    var main = new demoapplication();     var maintype = main.gettype();     var methodinfo = maintype.getmethod("othermethod");     var targetexpression = expression.parameter(maintype, "this");     var parameterexpressions = methodinfo.getparameters().select(info => expression.parameter(info.parametertype, info.parametertype.name)).toarray();     var body = expression.call(targetexpression, methodinfo, parameterexpressions); // {this.othermethod(context, person, packet)}     var lambdaparameters = new list<parameterexpression> { parameterexpressions[0] };     var lambda = expression.lambda(body, lambdaparameters); // {context => this.othermethod(context, person, packet)}     var lambdadelegate = lambda.compile(); // error


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