python - the code for linear sequential search is working for single digit numbers but its not working for two digit no - 


def search(arr, x):    in range(len(arr)):        if arr[i] == x:           return       return -1    num=input("enter elements\n") input_numbers_list = [int(n) n in num.split()]  value=input("enter element searched") print(input_numbers_list) print(value) = search(num,value) if -1:    print("element not found") else:    print("element found @ specific position "+str(i))

right pass strings search. iterate on characters in input string, , check if character equals second string. consider this:

'12345'[2] == '3'

convert value int:

value = int(input('enter element searched'))

pass integers search, not input:

i = search(input_numbers_list, value)

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