if statement - if statment not printing code in c - 


#include <stdlib.h> #include <time.h> #include "stdio.h"  int main(int argc, char const *argv[]) {    int money;   int safety;   int health;   int happiness;   int question;   int anwser;   anwser = 0;   unsigned int iseed = (unsigned int)time(null);     srand(iseed);    printf("welcome mayor\n\ni hope new seat here\n\nyour days packed full of questions must anwser simpy y/n\n");   printf("oh @ that, first customer ready\n");   printf("oh watch out resources dont let them low or empeached dun dun dun\n\n");   question = rand() % 3 + 1;    switch (question)   {     case 1:     printf("hey mayor,can build swimming pool?\n1. yes\n2.no\n");     scanf("%d",anwser);     if (anwser == 1)//**this problem starts**     {         printf("thanks mayer!\n");         happiness ++;         money --;      }     else     {         printf ("):\n");     }     break;      case 2:     printf("hey mayor, can run fundraiser hospitals\n1. yes\n2.no\n");     scanf("%d",anwser);     if (anwser == 1)//other problem here     {           printf("best mayor ever\n");           health ++;     }     else     {         printf("ugh\n");     }   }   return 0; }

so im not sure going on here if statment not want exectue thr code within {} im begginer c programmer typographical error, apprecciated. you.

read scanf()'s documentation,

scanf("%d", &anwser); //          ^ address of operator (you must pass pointer  //                                 variable's //                                  address)

and also, should check return value ensure input valid , answer initialized input data.


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