java - Insert an element into an array sorted according to frequency, then sort the array by frequency again -


so asked asked write o(n) function, insertranked(int[] list, int item), insert element array sorted frequency (i have written boolean function check if int[] list sorted frequency). after inserting element array, array sorted again frequency.

for example, insertranked([65, 65, 65, 65, 1, 1, 1, 8, 8, 987, 987, 2, 2, 40], 2) should produce [65, 65, 65, 65, 1, 1, 1, 2, 2, 2, 8, 8, 987, 987, 40].

is possible in o(n)? have thought of storing elements , counts linkedhashmap , using collections.sort() time complexity of collections.sort() o(n*log(n)).

here's 1 approach start off based on count.

import java.util.arraylist; import java.util.hashmap; import java.util.treemap;      public class sortcount {         public static void main(string[] args) {             int nums[] = {([65, 65, 65, 65, 1, 1, 1, 8, 8, 987, 987, 2, 2, 40};             hashmap<integer,integer> counts = new hashmap<integer,integer>();              for(int = 0; < nums.length; i++) {                 if(counts.containskey(nums[                     integer c = counts.get(nums[i]) + 1;                     counts.put(nums[i], c);                 }                 else {                     counts.put(nums[i],1);                 }             }              valuecomparator<integer,integer> bvc = new valuecomparator<integer,integer>(counts);             treemap<integer,integer> sortedmap = new treemap<integer,integer>(bvc);             sortedmap.putall(counts);              arraylist<integer> output = new arraylist<integer>();             for(integer : sortedmap.keyset()) {                 for(int c = 0; c < sortedmap.get(i); c++) {                     output.add(i);                 }             }              system.out.println(output.tostring());         }     }  //which uses comparator class compare values in map:     import java.util.comparator;     import java.util.map;      public class valuecomparator<t1,t2 extends comparable<t2>> implements comparator<t1> {         map<t1,t2> base;         public valuecomparator(map<t1,t2> base) {             this.base = base;         }          @override         public int compare(t1 k1, t1 k2) {             t2 val1 = base.get(k1);             t2 val2 = base.get(k2);              return val1.compareto(val2);         }     }

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