bash loop mysql output multiple to variables -


new programming , need little help.

i need access mysql database , loop thru ‘ftpuser’ , ‘domain’ column give me output below

echo 2>&1 " 3cmd put -r /home/$ftpuser/backups/ s3://bucket-backup/$domainname/"

when run shell script below outputs ever user each domain

 3cmd put -r /home/user1/backups/ s3://bucket-backup/domain1.com/  3cmd put -r /home/user1/backups/ s3://bucket-backup/domain2.com  3cmd put -r /home/user1/backups/ s3://bucket-backup/domain3.com/  3cmd put -r /home/user2/backups/ s3://bucket-backup/domain1.com/  3cmd put -r /home/user2/backups/ s3://bucket-backup/domain2.com/  3cmd put -r /home/user2/backups/ s3://bucket-backup/domain3.com/

and on

the result im looking 

 3cmd put -r /home/user1/backups/ s3://bucket-backup/domain1.com/  3cmd put -r /home/user2/backups/ s3://bucket-backup/domain2.com/  3cmd put -r /home/user3/backups/ s3://bucket-backup/domain3.com/  3cmd put -r /home/user4/backups/ s3://bucket-backup/domain4.com/

here code

!/bin/bash

filelines=username=$(mysql -h localhost -u root -p -ss -e "use users; select ftpuser users; ")  filelines2=username=$(mysql -h localhost -u root -p -ss -e "use users; select domain users; ")  echo start  username in $filelines ;  domainname in $filelines2 ;  echo 2>&1 " 3cmd put -r /home/$username/backups/ s3://bucket-backup/$domainname/"  done done

store elements of filelines , filelines2 in separate bash arrays , loop once through index shown.

arr1=($filelines) arr2=($filelines2) in ${!arr1[@]}     echo 2>&1 " 3cmd put -r /home/${arr1[$i]}/backups/ s3://bucket-backup/${arr2[$i]}/" done

output:

 3cmd put -r /home/user1/backups/ s3://bucket-backup/domain1/  3cmd put -r /home/user2/backups/ s3://bucket-backup/domain2/  3cmd put -r /home/user3/backups/ s3://bucket-backup/domain3/  3cmd put -r /home/user4/backups/ s3://bucket-backup/domain4/

you can refer looping on arrays, printing both index , value understanding looping syntax.


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