python - Regex - match if the number of occurences of x is the same as y -


this question has answer here:

i try make regex matches if times x appears in string equal time y appears

for example: "..x..y..y.x.." should match example: "..x..y..y.x..x" should not match

it's part of more complex regex, can't using count function of python.

thanks help

you can use re.findall:

import re s = "..x..y..y.x.."  if len(re.findall("x", s)) == len(re.findall("y", s)):     pass

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