php - I am selecting a friend list using following query but it will also showing the user himself in list. I will pass id of user in $userid -


(select   `wp_users`.`id` ,         'friend' type,         concat(`wp_users`.`display_name`,' ',`wp_users`.`last_name`) title,         concat('https://eduncle-courses-cdn.saglus.com/library/',`wp_users`.`id` ,'/profile_pic/thumbnail/',`wp_users`.`user_img`) image,         `entrv_master_users_chat`.`type`,         `entrv_master_users_chat`.`message`,         `entrv_master_users_chat`.`type` msg_type,         `entrv_master_users_chat`.`created` msg_send,         `wp_users`.`display_name` sender_name,         (select count(id) `entrv_master_users_chat` `sender_id` = `wp_users`.`id` , `read` =0 , `receiver_id` = '$userid') unread_msg          `entrv_master_users_chat` left join `wp_users` on                      `wp_users`.`id` = `entrv_master_users_chat`.`sender_id`                      `entrv_master_users_chat`.`receiver_id`='$userid' group `entrv_master_users_chat`.`sender_id` )order type desc 


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