javascript - Find a space before some numbers(time format) in regular expression -


i have string , want regular expression find whether there space before number or not, if yes, add 1 space before that. example: "taxi cabs thurs-fri-sat 11:30pm-3:00am" , result: "taxi cabs thurs-fri-sat 11:30 pm-3:00 am"

i'm not regular expression expert, ended these 2 variants:

  1. first variant using callback function second parameter replace method: 

var str = 'taxi cabs thurs-fri-sat 11:30pm-3:00am';  var strupdated = str.replace(/\d?\d:\d?\d(am|pm)/g, function(m){    return m.replace(/(am|pm)/g, " $1");  });  console.log('old: ' + str);  console.log('new: ' + strupdated);

  1. second variant using expression second parameter replace method:

var str = 'taxi cabs thurs-fri-sat 11:30pm-3:00am';  var strupdated = str.replace(/(\d?\d:\d?\d)(am|pm)/g, "$1 $2");  console.log('old: ' + str);  console.log('new: ' + strupdated);  console.log('----------------------------------');  var str = 'another test 1:22 am. 12:05pm , 12:50pn ';  var strupdated = str.replace(/(\d?\d:\d?\d)(am|pm)/g, "$1 $2");  console.log('old: ' + str);  console.log('new: ' + strupdated);

now try explain regex :)

  • (\d?\d:\d?\d) - match digits 1:1, 11:22, 1:22, 11:2, brakes used make group later use in replace regex (second parameter of replace method)
  • (am|pm) - group ( create when put brackets ) match literal or pm

edit (in response comment)

what can propose take care cases 11am-6pm or 8a-6p in regex , not complicate current one. have on following code - second replace doing job:

var str = 'taxi cabs thurs-fri-sat 11:30pm-3:00am \r\n     11am-6pm or 8a-6p 11m-6m or 12a-15p';  var strupdated = str.replace(/(\d?\d:\d?\d)(am|pm)/g, "$1 $2").replace(/(\d?\d)(am|pm|a|p)/g, "$1 $2");  console.log('old: ' + str);  console.log('new: ' + strupdated);


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