android - RxJava. Call onError after onNext -


i want call onnext , call onerror method. can not it. can me? example:

observable.create(new observableonsubscribe<string>() {     @override     public void subscribe(observableemitter<string> e) throws exception {         e.onnext("value");         e.onerror(new exception("exc"));     } })         .subscribeon(schedulers.io())         .observeon(androidschedulers.mainthread())         .subscribe(new consumer<string>() {             @override             public void accept(@nonnull string s) throws exception {                 log.v("tag", s);             }         }, new consumer<throwable>() {             @override             public void accept(@nonnull throwable throwable) throws exception {                 log.v("tag", throwable.getlocalizedmessage());             }         });

output: exc

thrad.sleep(500) helps me, think wrong way

if don't specify delayerror = true in observeon operator end checking if terminated (onerror called) before ends emitting onnext called beforehand.

see documentation:

delayerror - indicates if onerror notification may not cut ahead of onnext notification on other side of scheduling boundary. if true sequence ending in onerror replayed in same order received upstream


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