Scala: Run function on only one member of a list -

i'm pretty new scala , trying run function on 1 member of list. given list looks like

val list = list("hi", "bye now", "see ya later")

i return list looks like

val list = list("hi", "bye now", "see", "ya", "later")

i know if run list.map(_.split(" "))

list = ("hi", "bye", "now", "see", "ya", "later"). so, how do using lamdas without doing

list.append(list(2).split(" ")) , list.remove(list(2))?

thanks in advance,

if you're intent on applying function specific entries in list, could:

list.zipwithindex.flatmap {   case (entry, idx) if (idx == 2) =>     entry.split(" ")   case (entry, idx) => list(entry) } 

this generalized little more going along lines of:

// add variance, curry, etc. needed... def flatmaponly[a](list: list[a], offsets: set[int], f: => seq[a]): list[a] =   list.zipwithindex.flatmap {     case (entry, idx) if (offsets.contains(idx)) =>       f(entry)     case (entry, _) => list(entry)   }  scala> flatmaponly(list("hi", "bye", "see ya later"), set(1, 2), { str: string => str.split(" ").tolist }) res39: list[string] = list(hi, bye, see, ya, later)