python - How to omit keys with empty (non-zero) values -


i have dict { 'a': 'a', 'b': 0, 'c': {} } , need omit keys have empty values (0 not considered empty). so, output of should { 'a': 'a', 'b': 0 }.

for { 'a': 'a', 'b': 0, 'c': { 'd': 'd' } } --> { 'a': 'a', 'b': 0, 'c': { 'd': 'd' } };

i tried {k: v k,v in my_dict.items() if not v}, i'm not sure how preserve 0s;

i'm looking https://lodash.com/docs/4.17.4#omitby

you can write function takes predicate filtering based on values:

def omit_by(dct, predicate=lambda x: x!=0 , not x):     return {k: v k, v in dct.items() if not predicate(v)}  dct = { 'a': 'a', 'b': 0, 'c': {} } print(omit_by(dct)) # {'a': 'a', 'b': 0}  dct =  {'a': 'a', 'b': 0, 'c': { 'd': 'd' } } print(omit_by(dct)) # {'a': 'a', 'b': 0, 'c': {'d': 'd'}}

simply change predicate suites you.


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