c++ - Why can`t I put a zero in front of an integer in an "if" statement -


why little cheat code not work when put 0 in front of it. when take out , put little cheat code works fine, when put in , put cheat code in skip right over.

#include <iostream> #include <random>  int main() {     bool correct = false;     std::cout << "put number 1 100" << std::endl;     int guess = 0;     std::cin >> guess;     std::random_device rd;     std::mt19937 mt(rd());     std::uniform_int_distribution<int> rnd(0, 101);     int answer = rnd(mt); //random number     while (correct == false)     {         if (guess == answer)         {             std::cout<<"you got it!!!"<<std::endl;             correct = true;         }         else if (guess == 01010101)#<--------------------problem         #it works when 1010101         {             std::cout<< answer<< std::endl;             std::cout << "put number 1 100" << std::endl;             std::cin >> guess;         }         else if (guess > answer)         {             std::cout<<"your guess high guess again"<< std::endl;             std::cout << "put number 1 100" << std::endl;             std::cin >> guess;         }         else if (guess < answer)         {             std::cout<<"your guess low guess again"<< std::endl;             std::cout << "put number 1 100" << std::endl;             std::cin >> guess;         }          else         {             std::cout << "put number 1 100" << std::endl;             std::cin >> guess;         }       } }

a leading 0 on numeric literal indicates literal expressed in octal (base 8) notation1, (obviously) has different magnitude same digits interpreted decimal (base 10).

the octal number 01010101 equal decimal number 266305.

1 unless leading 0 followed x, it's interpreted hexadecimal (base 16).


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