Python matplotlib bars overlapping although width < 1 -
i trying plot number of bar charts matplotlib having 26 timestamps / slots @ x-axis , 2 integers y-axis. data sets scales fine, in cases matplotlib lets bars overlap:
left overlapping , not aligned xticks, right 1 ok
so instead of giving enough space bars overlapping although width set 0.1 , datasets have 26 values, checked.
my code plot these charts follows:
# plot rows = len(data_dict) // 2 + 1 fig = plt.figure(figsize=(15, 5*rows)) gs1 = gridspec.gridspec(rows, 2) grid_x = 0 grid_y = 0 dataset_name in data_dict: message1_list = [] message2_list = [] ts_list = [] slot_list = [] slot, counts in data_dict[dataset_name].items(): slot_list.append(slot) message1_list.append(counts["message1"]) message2_list.append(counts["message2"]) ts_list.append(counts["ts"]) ax = fig.add_subplot(gs1[grid_y, grid_x]) ax.set_title("activity: " + dataset_name, fontsize=24) ax.set_xlabel("timestamps", fontsize=14) ax.set_ylabel("number of messages", fontsize=14) ax.xaxis_date() hfmt = matplotdates.dateformatter('%d.%m,%h:%m') ax.xaxis.set_major_formatter(hfmt) ax.set_xticks(ts_list) plt.setp(ax.get_xticklabels(), rotation=60, ha='right') ax.tick_params(axis='x', pad=0.75, length=5.0) rects = ax.bar(ts_list, message2_list, align='center', width=0.1) rects2 = ax.bar(ts_list, message1_list, align='center', width=0.1, bottom=message2_list) # update grid position if (grid_x == 1): grid_x = 0 grid_y += 1 else: grid_x = 1 plt.tight_layout(0.01) plt.savefig(r"output_files\activity_barcharts.svg",bbox_inches='tight') plt.gcf().clear() the input data looks follows (example of plot overlapping bars, second picture)
slot - message1 - message2 - timestamp 0 - 0 - 42 - 2017-09-11 07:59:53.517000+00:00 1 - 0 - 4 - 2017-09-11 09:02:28.827875+00:00 2 - 0 - 0 - 2017-09-11 10:05:04.138750+00:00 3 - 0 - 0 - 2017-09-11 11:07:39.449625+00:00 4 - 0 - 0 - 2017-09-11 12:10:14.760500+00:00 5 - 0 - 0 - 2017-09-11 13:12:50.071375+00:00 6 - 0 - 13 - 2017-09-11 14:15:25.382250+00:00 7 - 0 - 0 - 2017-09-11 15:18:00.693125+00:00 8 - 0 - 0 - 2017-09-11 16:20:36.004000+00:00 9 - 0 - 0 - 2017-09-11 17:23:11.314875+00:00 10 - 0 - 0 - 2017-09-11 18:25:46.625750+00:00 11 - 0 - 0 - 2017-09-11 19:28:21.936625+00:00 12 - 0 - 0 - 2017-09-11 20:30:57.247500+00:00 13 - 0 - 0 - 2017-09-11 21:33:32.558375+00:00 14 - 0 - 0 - 2017-09-11 22:36:07.869250+00:00 15 - 0 - 0 - 2017-09-11 23:38:43.180125+00:00 16 - 0 - 0 - 2017-09-12 00:41:18.491000+00:00 17 - 0 - 0 - 2017-09-12 01:43:53.801875+00:00 18 - 0 - 0 - 2017-09-12 02:46:29.112750+00:00 19 - 0 - 0 - 2017-09-12 03:49:04.423625+00:00 20 - 0 - 0 - 2017-09-12 04:51:39.734500+00:00 21 - 0 - 0 - 2017-09-12 05:54:15.045375+00:00 22 - 0 - 0 - 2017-09-12 06:56:50.356250+00:00 23 - 0 - 0 - 2017-09-12 07:59:25.667125+00:00 24 - 0 - 20 - 2017-09-12 09:02:00.978000+00:00 25 - 0 - 0 - 2017-09-12 10:04:36.288875+00:00 does know how prevent happening? calculated 26 bars every chart , expected them have equally width. tried replace 0 1e-5, did not prevent overlapping (which post proposed).
the width of bar width in data units. i.e. if want have bar of width 1 minute, set width
plt.bar(..., width=1./(24*60.)) because numeric axis unit datetime axes in matplotlib days , there 24*60 minutes in day.
for automatic determination of bar width, may want have bar width smallest difference between 2 successive values input time list. in case, following trick
import numpy np import matplotlib.pyplot plt import datetime import matplotlib.dates t = [datetime.datetime(2017,9,12,8,i) in range(60)] x = np.random.rand(60) td = np.diff(t).min() s1 = matplotlib.dates.date2num(datetime.datetime.now()) s2 = matplotlib.dates.date2num(datetime.datetime.now()+td) plt.bar(t, x, width=s2-s1, ec="k") plt.show() 
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