Python if-else statement order -


my problem similar one: python if-elif statements order answer is:

    #this answer given question linked      directions = []         if <the obstacle has free tile on right>:               directions.append(move_right)         if <the obstacle has free tile on left>:               directions.append(move_left)      if not directions:           stop()     else:          random.choice(directions)()

now, question how input if statements list direction=[] ? valid data type? edit: want know how able apply code above. let's there's object in maze , when reaches intersection code have:

   if (a in intersection):         a.forward()    elif (forward().doesntexist):         a.left()    elif (left().doesntexist):         a.right()   ......

but code mean he'd go forward first, left, right, etc. want direction random may go right/forward/left first.

import sys import random  # example "free tile" free_tile = (0,5)  def move_right():     my_pos = free_tile     return my_pos  def move_left():     my_pos = free_tile     return my_pos  def stop():     print 'bye!'     sys.exit(0)  directions = []  if free_tile == (0,5):     print 'moving right'     directions.append(move_right())  if free_tile == (0,6):     print 'moving left'     directions.append(move_left())  elif not directions:     print 'no directions...exiting...'     stop() else:     print random.choice(directions)  print 'current location', directions

demo:

moving right (0, 5) current location [(0, 5)]

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