java - Find If Two Strings are Permutations While Prioritizing Time/Long Strings/Short Strings -


so trying find best implementation methods find if 2 strings permutations of each other 3 cases: 1. long input strings, 2. long input strings , prioritizing speed, , 3. short input strings , prioritizing space.

my implementation first case using xor:

if (string1.length() != string2.length())     {         return false;     }     int find = 0;     for(int = 0; < string1.length();i++ ){         find ^= string1.charat(i) ^ string2.charat(i);     }       return find == 0;

my implementation second case using hash map or hash set haven't implemented yet.

my implementation last 1 sorting strings , using java .equals compare if strings equal.

if (string1.length() != string2.length()) {         return false;     }     char[] = string1.tochararray();     char[] b = string2.tochararray();      arrays.sort(a);     arrays.sort(b);      return arrays.equals(a, b);

** test input: 2 empty strings; "ab" "ba"; "abc" "acd"; "rats" "star**"; "\u263a bye now!!" "!bye now! \u263a"

would these 3 implementations best these cases?


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