c++ - Scanning User Input for Strings Declared in an Array -


i creating program scans user input words listed in array. find() function seems it'll work, can't find showing how implement want do. i'm pretty new programming (obviously).

#include <iostream> #include <time.h> #include <stdlib.h> #include <string> #include <vector> #include <algorithm>  using namespace std;  string subj [5]={"i","he","she","we","they"}; string verb [5]={" like"," hate"," sacrifice"," smell"," eat"}; string obj [5]={" bacon","s cats","s bagels","s children","s cops"}; string greeting [5]={"how you","how's going","sup dude","hey","hello"}; string negvibe [4]={"bad","terrible","lousy","meh"};  string userfeeling;  int main() {     srand(time(0));     int rando = rand() %5;//generates random number between 0 , 4     int rando1 = rand() %5;     int rando2 = rand() %5;      cout << greeting [rando1] << "." << endl;     getline(std::cin,userfeeling);      if .... // has done here?          find(negvibe, negvibe + 4, userfeeling) != negvibe + 4);     // that?      // ...     {         cout << subj[rando] << verb[rando1] << obj[rando2] <<"." <<endl;     }     return 0; }

that find function find element of negvibe array equal userfeeling. if checking whether element of negvibe substring of userfeeling, should loop through negvibe , use std::string::find method.

bool found_negvibe = false; (int = 0; < sizeof(negvibe) / sizeof(*negvibe); i++) {     found_negvibe = found_negvibe || userfeeling.find(negvibe[i]) != string::npos; }

also, don't need specify size of negvibe array, can write this:

string negvibe[] = {"bad","terrible","lousy","meh"};

one more thing, might prefer use std::vector on array, if because c++'s faculties getting size of vector more succinct getting size of array.

vector negvibe = {"bad","terrible","lousy","meh"};  bool found_negvibe = false; (int = 0; < negvibe.size(); i++) {     found_negvibe = found_negvibe || userfeeling.find(negvibe[i]) != string::npos; }

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