string - Program C count words (excluding numbers) -

i have come across lot of counting words examples (like 1 in link below):

counting words in string - c programming

if(str[i]==' ') {     i++; } 

and digit is:

if(str[i]>='0' && str[i]<='9') {     i++; } 

but if input 'i have 12 apples.' , want output show "word count = 3"?

assuming don't have words contain alphanumeric combinations, "foo12", combine code snippets, this:

#include <stdio.h> #include <string.h>  int main(void) {     char str[] = "bex 67 rep";     int len = strlen(str);     int count = 0, = 0;     while(str[i] != '\0')     {         if(str[i] == ' ')         {             if(i + 1 < len && ! (str[i + 1] >= '0' && str[i + 1] <= '9') && str[i + 1] != ' ')                 count++;         }         i++;     }     printf("word count = %d\n", count + 1); // word count = 2     return 0; } 

where loop on every character of string, , when find whitespace, check - if not @ last character of string - if next character not digit or whitespace. if that's case, can assume whitespace encountered precedended of word, incease count.

notice senteces not start whitespace (which assumption answer), number of words 1 more count.

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in real life, use strtok() , check every token validity, since that's approach demonstration , should considered bad approach.