regex - Fetch date time part from filename in R -

i want fetch date , time part filename given below:

filename<-"/abc/def/ghi/jk.0m25.2015011500.f264.path2.pathd254004.nc" 

i tried below code fetch desired part:

 dt<- sub('^[^.]+.(\\d+)+[\\w\\d].*','\\1',filename)#not working 

here date , time part date:20150115 time:00

dtm <- strptime(c("2015-01-15 00:00:00"), format = "%y-%m-%d %h", tz = "est") 

then want add hours(which 264 in filename (/.f264.path2.)) dtm object.

final_dt<- dtm+264(hrs) 

final_dt contains both date , time.

once value of final_dt, want add column dataframe given below:

# creating dataframe  long<-c(106.61291,-81.97224,-84.4277,-97.66631,-72.68604) lat<-c(35.04333,33.37378,33.64073,30.19743,41.93887) xy <- data.frame(long, lat)  #desired output   actual_date time final_date time     long      lat 1 2015-01-15  00   2015-01-26 ...        106.61291 35.04333 2 2015-01-15  00   2015-01-26 ...        -81.97224 33.37378 3 2015-01-15  00   2015-01-26 ...         -84.42770 33.64073 4 2015-01-15  00   2015-01-26 ...          -97.66631 30.19743 5 2015-01-15  00   2015-01-26 ...          -72.68604 41.93887 

i'll try best clear up, let me start saying question unclear,

dt<- sub('^[^.]+.(\\d+)+[\\w\\d].*','\\1',filename)#not working 

it appears asking solution part?

assuming date time sequence of 10 digits in row can appear in filename, can use following regex

"\.\d{10}\." 

then parse sub strings (yyyy, mm, dd, tt) date-time using substring function. , pass strptime method.

final_dt<- dtm+264(hrs) 

for addition/increment of time intervals, strptime appears accept integers seconds try

final_dt<- dtm + (264*60*60) 

where 60*60 60 minutes/hour * 60 seconds/minute unit conversion.

xy <- data.frame(long, lat) 

if have dtm's in vector, can use them @ time of creation of xy such as:

xy  <- data.frame(dtm_vector, long, lat) 

(p.s. should try adding more tags question, such 'regex', since biggest hurdle in scenario)