How to calculate the sum of a series with the nth term being user input in Java -


i trying compute summation , pi. have gotten pi calculation work, having difficulty on summation. output of summation supposed calculate 1/3 + 3/5 + 5/7 .... number/n nth term user input, uncertain calculation. if input 5 output should calculate 1/3 + 3/5, code add 5 terms 1/3 + 3/5 + 5/7 + 7/9 + 9/11, doing wrong? here code:

import java.util.scanner; public class n01092281 {     public static void main(string[] args) {       scanner input = new scanner(system.in);       system.out.println("enter nth term series.");       double userinput = input.nextint();          double sum = 0.0;       for(int = 2; <= userinput*2; i+=2) {          sum += ((double)(i-1)/(i+1));        }       system.out.printf("the sum of series %12.12f" , sum);        double pi = 0;       (int counter = 1; counter < userinput; counter++){          pi += 4 * (math.pow(-1,counter + 1)/((2*counter) - 1));       }       system.out.printf(" ,the computation of pi %1.12f",  pi);    }    }

i guess, doing right calculation. changed way using i. need update count how many times go.

this how changed it

      double userinput = 11;       int count =0;       if(userinput>=3){           count =(int)( userinput-1)/2;       }       double sum = 0.0;       for(int = 1; <= count; i++) {          sum += ((double)(2*i-1)/(2*i+1));          system.out.print((2*i-1)+"/"+(2*i+1)+' ');        }       system.out.println();       system.out.printf("the sum of series %12.12f" , sum);

output:-

1/3 3/5 5/7 7/9 9/11  sum of series 3.243578643579

here printing series, make clear you.


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