How to create list by deriving another list in scala -


i have list follow

list[string] = list(gateway = msc050, sequence = 176484,gateway = msc050, sequence = 176485) 

i want create referring above follow

list[string] = list(50176484,50176485) 

here have merger last 2 digit of gateway , sequence list. can 1 on this?

assuming list missing quotes:

  val input: list[string] = list("gateway = msc050", "sequence = 176484", "gateway = msc050", "sequence = 176485")    input.grouped(2).map {     l => l(0).takeright(2) + l(1).split(' ').last   }.tolist 

output:

list(50176484, 50176485) 

grouped(2) allow iterate on every gateway/sequence pair. need last 2 digits gateway, , number sequence. i've done takeright gateway, , splitting on spaces sequence (assuming sequence strings have space after equals).


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