javascript - How to set relative path resolution based on 'dist' folder -

when creating npm package, quite common , convenient structure so:

root   / dist   / src   / package.json 

where package.json:

{   "main": "dist/index.js"   "files": [ "dist" ] } 

the drawback of approach is, when consumer wants require files using relative path, needs include dist folder. e.g. const abc = require('my-package/dist/x/y/abc');

is there way tell nodejs resolve relative path based on path.dirname(main) or similar?

update: clarify, related relative/deep resolution, not export hoisting in es6. controversial subject should done @ all, consumer coupled internal folder structure of package.

update 2: want achieve concept of "sub-module" (similar namespacing). example, folder structure looks this:

root   / dist      / testutil.js      / index.js 

testutil.js contains useful functions testing. since not used in normal use, don't want export them @ top-level. i.e., instead of:

// index.js export * './testutil' 

i do:

// index.js import * testutil './testutil' export { testutil } 

however, still expose testutil module namespace @ top-level , hard use:

// consuming.js import { testutil } 'my-package' const { funca, funcb } = testutil 

it better if can "tug" under relative path:

// consuming.js import { funca, funcb } 'my-package/testutil' 

currently, without solving 'dist' issue, have instead:

// consuming.js import { funca, funcb } 'my-package/dist/testutil' 

you can set node_path environment variable, , should trick:

export node_path=./dist 

there other patterns try out here.