jQuery .is('input:hidden') function returns true if any input type element is not visible -
you can use jquery .is() function determine if html element of specific type. example,
$(x).is('input:text')
will return true if x references a
<input type="text'>
element.
i noticed if make text (or other) input element invisible, use $(x).is('input:hidden')
, returns true
.
to match
<input type="hidden">
elements, must do
$(x).is('input[type=hidden]')
am missing here, or bug? thought :hidden referred element type, not visibility of element.
here's requisite codepen: https://codepen.io/anon/pen/lzpdaj
first of all, jquery method is
, not checking element type, checking against jquery selector - https://api.jquery.com/is/
as selector, in css :hidden
match type hidden, same selector has broader meaning in jquery.
from docs - https://api.jquery.com/hidden-selector/
elements can considered hidden several reasons:
- they have css display value of none.
- they form elements type="hidden".
- their width , height explicitly set 0.
- an ancestor element hidden, element not shown on page.
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