How can remove http(s), www(n) and public suffixes in ruby? -


input => expected output

  1. https://mail.google.com.au => mail.google
  2. http://www.google.in => google
  3. https://www9.calendar.google.co.uk => calendar.google
  4. https://www12.stage.calendar.google.co.uk => stage.calendar.google
  5. www.blog.botreetechnologies.com => blog.botreetechnologies

update

t = uri.parse 'http://www.google.com' t.host #=> "www.google.com"  uri.split 'http://www.google.com' #=> ["http", nil, "www.google.com", nil, nil, "", nil, nil, nil] uri = uri.parse("http://www.google.co.uk") #=> #<uri::http http://www.google.co.uk> domain = publicsuffix.parse(uri.host) #=> #<publicsuffix::domain:0x00000003c538e0 @sld="google", @tld="co.uk", @trd="www"> domain.sld #=> "google"  uri = uri.parse("http://www.mail.google.co.uk") #=> #<uri::http http://www.mail.google.co.uk> domain = publicsuffix.parse(uri.host) #=> #<publicsuffix::domain:0x00000002e97bc0 @sld="google", @tld="co.uk", @trd="www.mail"> domain.sld #=> "google"  %w[http://www.example.com/page http://blog.example.com/page].each |u|   puts uri.parse(u).host.sub(/^www\./, '')   end   # example.com # blog.example.com  uri = uri.parse("www.pinkpoodles.com.au") #=> #<uri::generic www.pinkpoodles.com.au> uri.host #=> nil

i can't think of "one-liner", work:

require 'uri' require 'public_suffix'  def simple_host(uri)   uri = uri(uri)   uri = uri("http://#{uri}") unless uri.scheme   domain = publicsuffix.parse(uri.host)   trd = domain.trd   if trd     trd = trd.split('.')     trd.shift if trd.first.start_with?('www')   end   [*trd, domain.sld].join('.') end  simple_host('https://mail.google.com.au')                #=> "mail.google" simple_host('http://www.google.in')                      #=> "google" simple_host('https://www9.calendar.google.co.uk')        #=> "calendar.google" simple_host('https://www12.stage.calendar.google.co.uk') #=> "stage.calendar.google" simple_host('www.blog.botreetechnologies.com')           #=> "blog.botreetechnologies"

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